这里好冷清,再出两个数学/物理题,活跃一下气氛
登录 | 论坛导航 -> 华新鲜事 -> 求学狮城 | 本帖共有 29 楼,当前显示第 22 楼 : 从楼主开始阅读 : 本帖树形列表 : 返回上一页
作者:1300cc (等级:3 - 略知一二,发帖:714) 发表:2008-06-21 03:28:25  22楼 
speed converge to v1+v2It can be proved (you can check my answers in "第二题:条件足够了"). Ok, I get your meaning. You are trying to discretize the problem using time slice of 1 sec, right? You can use this kind of method, although it makes problem unnecessary complex (remember not to fix the time slice, you should calculate the limit when time slice approach 0). I use this approach as well, of course, for computer programming, and the time slice is usually set to sufficiently small value to get accuracy answer. The cause of the problem is that you set the time slice to 1 sec. During this 1 sec period, the worm moves some not negligible distance already. Using time slice of 1, the worm speed: .01 * ( 1 + 1/n + 1/n*(n-1) + 1/ n*(n-1)*(n-2) ... ) < .01 * ( 1 + 1/n + 1/n + ... ) = .02 I.e. the method itself poses a problematic constraint on the problem. Try set the time slice smaller.
actually
if i assume it will never reach, i can choose the upper limit of speed series as :

0.01,
0.01+0.01/1,
0.01 + (0.01 + 0.01 / 1 ) / 2,
0.01 + ( 0.01 + (0.01 + 0.01 / 1 ) / 2 ) / 3,
...
......
0.01 + ( 0.01 + ( 0.01 + ... + 0.01/1)/2/3 ... ) / n

if i assume it will reach, i can choose the lower limit of speed series as :
0.01,
0.01+0.01/2,
0.01 + (0.01 + 0.01 / 3 ) / 3,
0.01 + ( 0.01 + (0.01 + 0.01 / 2 ) / 3 ) / 4,
...
......
0.01 + ( 0.01 + ( 0.01 + ... + 0.01/2)/3/4 ... ) / n+1
----------------- 人无痴者,无可与之交,因其无真气也; 人无嗜者,无可与之交,因其无深情也。 唯有真气与深情入心,才会在本当得意之时泪如泉涌。 ----<<喜泪>>
欢迎来到华新中文网,踊跃发帖是支持我们的最好方法!原文 / 传统版 / WAP版只看此人从这里展开收起列表

本帖共有 29 楼,当前显示第 22 楼,本文还有 N-1 层楼,要不你试试看:点击此处阅读更多 >>



请登录后回复:帐号   密码