华新 - It seems that you are confused...

It seems that you are confused...

作者：Flying (等级：18 - 华新水车，发帖：16849) 发表：2003-06-04 14:35:00　楼主　关注此帖评分：

followon questionThanks, VeryGood. The compiler really complains about non-static member functions as shown in error message. My followon question is that: in a class defintion, there are acutally many non-static member function. Here the member function is private, does it matter? Is it possible to define a non-static private member function? TIA

It seems that you are confused...

1) The sample you gave above is NOT a declaration of member function. Instead, the typdef statement simply aliases a data type of member function pointer as "Omf" for the ease of reference.

2) No matter farray is declared as static or not, the syntax is acceptable! That is, there is NO compelling reason that farray must be declared static. Please double check.

Flying @way

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作者：Flying (等级：18 - 华新水车，发帖：16849) 发表：2003-06-04 16:13:48　 2楼评分：

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在 graduating 的大作中提到：

1-yes, 2-noI agree with your first point. It is really just aliasing. I had mis-used some words such as static functions. It is not private function. farray is a pointer to array of functions. farray is a private member of class Object. So the problem is that the keyword static is not allowed to be omitted, otherwise compiler complains as shown in the error message [quote] menu1.cpp:17: 'void (Object::* Object::farray[3]()' is not a static member of 'class Object' [/quote] So you see the problem?

I saw your problem. But I don't think that's the

point.

I compiled the following code using g++ version 2.95.2 on Solaris:

class Object {
private:
typedef void (Object::*Omf)();
/*static*/ Omf farray[3];
};

Compilation gave no error. I suppose the error was caused by other factors.

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