using linux/glibc? Segfault because you damaged the link listof freed memory chunks.
bype 0-8 of a freed memory chunk contains pointers to the previous/next freed chunks. in
for (int i = 0; i < 8; i ++)
flag[i] = true;
you destroyed the link list. When you try to free the next chunk (darray), free() tries to merge the two adjacent freed chunks. As the link list is corrupted, you see a segfault.
There are two ways to avoid segfault with you wrong program:
1.
#include
using namespace std;
int main ()
{
bool * flag = new bool[16];
delete [] flag;
double * darray = new double[10];
for (int i = 0; i < 8; i ++)
flag[8+i] = true;
cout (more...)
a mistake
2nd case:
double * darray = new double[1];
should be:
double * darray = new double[2];
double[1] needs only 8 bytes, so first chunk (released when you delete flag) is reused.
change double[2] still does not generate segfault.
double * darray = new double[1];
should be:
double * darray = new double[2];
double[1] needs only 8 bytes, so first chunk (released when you delete flag) is reused.
change double[2] still does not generate segfault.
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