why does not "g++ -Wall" give warning message when compiling the following code?When u run the code, you will get segmentation fault as "flag" is used after the memory released, however, the segmentation fault happens at the "delete [] darray" sentence, why is it so? I thought it should happen at "flag[i] = 8". the compiler should be able to detect such mistake, why does not "g++ -Wall" give any warning message? please reply. #include using namespace std; int main () { bool * flag = new bool[8]; delete [] flag; double * darray = new double[10]; for (int i = 0; i < 8; i ++) flag[i] = true; cout

delete array; not delete [] array;delete [] arr; is equivalant to delete arr[0]; delete arr[1]; ... delete arr[k]; ------------------------------------------------ defination from msdn: The delete operator destroys the object created with new by deallocating the memory associated with the object. ------------------------------------------------ however your array is array of primative type bool now try this Class Bool { public bool myBool; }; Bool *flag2 = new Bool[8]; delete [] flat2;

no la...as simon said, object vs primitive data type