I propose.Those ranked last 3 for more then 2 times to be demote to unranked player. In this way, the lousy players will either need to buck up their standard or they refrain from joining national to become Santa Clause.
This is quite a good suggestion and it's new to singapore.
Given the number of B div competitions we have yearly. I reckon A division will be swarmed with lots of B div players in the years to come. It's important tht sixga do some quality control. Probably not bottom 2. Maybe bottom 5 in 2 consecutive years.
But having enough players and degrading players is a different issue. Moreover we have more than one B division open each year. This is a recent issue and would surely increase the number of participants in the next 5 years.
Another Suggest:: Minimum Points SystemIn Group A competitions, B-graded players must attain a minimum of 2 pts and A-graded players must achieved 4 points out of a total match of 9 matches. So to said, players when decided to participate in the annual match will have to try his or her best to achieve the min. points to continue carrying his 'Grade'.
If a B-graded player fails to gain 2pts in the last 2 years of participation, it will be wiser or more compatible for him to play in Group B games when chances are better and skills are more comparable. For A-graded players, failure to achieve the points will be demoted to Grade B. If next 2 years continue to achieve 2 pts, he will play in the Group B.
This can perhaps keep the chess standard of Sg, making matches more competitive and title-holders more current.
Just expressing my personal opinion. No offence to anyone or organisation!
yeah I reckon it's feasible
I think It doesn't really matter whether Sixga degrade players or not. What's most important is there are measures to control the quality of the games so it does not drop due to the increasing number of B division players (max 8 a year) in future national competitions.
How about black continue this move?After black 车2退6,red 车4+6,你将5进1,黑马3+2你没那么容易KO你如再车2+4红可以炮6+1
炮5平2 continue can?
My thinking line is
if black 炮5平2 red 马2+1 black 车2平4, 车4退1 将5-1, 马1+3 士4+5,
车4平5 将5平4,马3-5 车4-4
由于是比赛这步棋估计算不清。说实话很难说。但给我选我可能选多子方
还有多一个变化是可以考虑就是你车2+4他可能还有将4+1 instead of 炮6+1。但这棋比较复杂还很难讲
但如是根据你的想法。感觉是红好因为黑车被吊住。可能可以车9平8
炮5平2 red 马2+1 black 车2平4, 车4退1 将5-1, 马1+3 士4+5,
车4平5 将5平4,马3-5 车4-4
.